1.7x^2+2x=70

Solution for 1.7x^2+2x=70 equation:

1.7x^2+2x=70

We move all terms to the left:

1.7x^2+2x-(70)=0

a = 1.7; b = 2; c = -70;
Δ = b2-4ac
Δ = 22-4·1.7·(-70)
Δ = 480
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{480}=\sqrt{16*30}=\sqrt{16}*\sqrt{30}=4\sqrt{30}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-4\sqrt{30}}{2*1.7}=\frac{-2-4\sqrt{30}}{3.4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+4\sqrt{30}}{2*1.7}=\frac{-2+4\sqrt{30}}{3.4}
$